Problem with casting

[vinayak manda]

Are there different rules for casting for different types of operators(like assignment and compound operators)
I mean when
byte b=1;
long l=1000;
b=(byte)l; //compiler asks for casting here.

And when
byte b=1;
long l=1000;
b+=l; //which is b=b+l,and the result of b+l here is long,then why doesn't compiler ask for casting when assigning to long to byte as above exmaple.And will byte store 1000.

Please help,

[Peter den Haan]

b += l;

is not equivalent to

b = b + l;

but to

b = (byte)(b + l);

- Peter