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Can someone explain this ???

Rob Hopping

Joined: Oct 29, 2004
Posts: 4
I've set convertionValue equal to (binaryString.charAt(0)) but when I print them out I get two different answers.

The following produces:


Why is it addind 48 to convertionValue?

// main line of program
public static void main (String[] args) {

String binaryString = ("3677895775421");
int convertionValue;

convertionValue = (binaryString.charAt(0));

Dun Dagda
Ranch Hand

Joined: Oct 12, 2004
Posts: 54
That is because charAt will return the ASCII code of the character at that position in the String. The ASCII code of the character 0 (zero) is 48, character 1 is ASCII 49, etc.
So to convert the character code for the character "1" to its numerical equivalent, you need to subtract 48 from the character code.


SCJP 1.4<br />SCWCD (in progress)
marc weber

Joined: Aug 31, 2004
Posts: 11343


"We're kind of on the level of crossword puzzle writers... And no one ever goes to them and gives them an award." ~Joe Strummer
Dun Dagda
Ranch Hand

Joined: Oct 12, 2004
Posts: 54
Here's something that might help you out.

Try pasting this into a .java file and compiling and running it yourself.

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