can we store an integer in a byte array

[zheng da]

I want to transform an integer to a byte array of size 4.
Can we do that?

[ankur rathi]

int i[]={1,3,5,7};
byte b[]= new byte[i.length];

for(int j=0; j<i.length; j++) {
b[j] = (byte)i[j];
System.out.println(b[j]);//optional
}

Try , it may help you ...

[Peter Chase]

Originally posted by zheng da:
I want to transform an integer to a byte array of size 4.
Can we do that?

Yes. This should do it, I think. Run the loop the other way to swap between big-endian and little-endian.

int value = .... ;
byte b = new byte[4];
for (int i=0; i < 4; ++i)
{
  b[i] = (byte) (value & 0xFF);
  value = value >> 8;
}

[Ernest Friedman-Hill]

If you need to do a lot of these, it may make sense to use a ByteArrayOutputStream fed by a DataOutputStream.

ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
for (int i=0; i<100; ++i)
  dos.writeInt(i);
byte[] all100Integers = baos.toByteArray();