Testing Strings

[Timothy Willis]

Hi,

Having a few problems with strings. I am trying to write a program so that I can input two strings, and then test the strings to see whether they are identical or, if not, which comes first in the alphabet.

I have this code and it wont compile.

 
public class Strings
{
   public static void main (String[] args)
   {
   
System.out.print("Please Enter First String: ");
string1 = EasyIn.getInt();
System.out.print("Please Enter Second String: ");
string2 = EasyIn.getInt();
 
if (string1.equals(string2))
   System.out.println("The Strings are Identical");
else if (string1.compareTo(string2) >0 )
   System.out.println("The String1 comes first in alphabetical Order");
else if (string1.compareTo(string2) < 0)
   System.out.println("The String2 comes first in alphabetical order");
  
}
    }

Any help would be appreciated.

[Mike Gershman]

What error message are you getting?

[Timothy Willis]

Error message:

Cannot resolve symbol - variable string 1

[Ernest Friedman-Hill]

Well, you don't declare string1 anywhere, do you? A declaration include the variables type and name and optionally an initializer. You first use "string1" without having every declared it to be a String.

When you do, I suspect you'll have a problem assigning what "getInt()" returns to a String variable -- maybe there's a getString() method you should use instead?

[Timothy Willis]

So like this:

public class Strings
{

public static void main (String[] args)
{
String string1, string2;

System.out.print("Please Enter First String: ");
string1 = EasyIn.getString();
System.out.print("Please Enter Second String: ");
string2 = EasyIn.getString();

if (string1.equals(string2))
System.out.println("The Strings are Identical");
else if (string1.compareTo(string2) >0 )
System.out.println("The First String comes first in alphabetical Order");
else if (string1.compareTo(string2) < 0)
System.out.println("The Second String comes first in alphabetical order");

}
}

[Mike Gershman]

What is "EasyIn.getString()"?