Help with getting a specific value from a String

[Eric Martin]

I have a String that I need to break into parts to use one of the values.

Example:
// This value actually comes from request.getReqestURI();
String uri = "/Servlet/Case.html";

What I need is the "Case" value...it won't always be "Case". The format will always be ContextPath + / + pageName and what I need is the pageName without the .html.

TIA

[David C. Meyers]

May I suggest:

String uri = "/Servlet/Case.html";
int lastSlashIndex = url.lastIndexOf('/');
int lastDotIndex = url.lastIndexOf('.');
String name = uri.substring(lastSlashIndex, lastDotIndex);

Good luck.

[Eric Martin]

Much more elegant than what I had =)

I just had to change:
String name = uri.substring(lastSlashIndex, lastDotIndex);
to:
String name = uri.substring(lastSlashIndex + 1, lastDotIndex);

Thanks a bunch!

[James Carman]

If you're programming with servlets, you can always ask the request what the context path is rather than parsing it out of the URI.

[Eric Martin]

Right, but in my example, that would just give me /Servlet and I wanted Case. Correct me if I am wrong.

[Mark Spritzler]

THIRD AND FINAL NOTICE

You had it correct before, why did you change it back?

"Eric"-
Welcome to the JavaRanch! Please adjust your displayed name to meet the

JavaRanch Naming Policy.

You can change it

here.

Thanks! and welcome to the JavaRanch!

Mark

[James Carman]

  
The context path is <%=request.getContextPath()%>!

When I access the page it says...

The context path is /jsp-examples!

[ August 06, 2005: Message edited by: James Carman ]