Triangular Output

[Moni Marva]

I am trying the program that can generate following output

0
1 4
9 16 25
36 49 64 81

I tried to do it in following ways, but not getting the exact output.

 
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
 
public class DisplayTriangle
{
 
   public static void skip(int n)
   {
      for (int i = 0; i <= n; i++)
         System.out.print(" ");
   }
 

   public static int squareNo(int n)
   {
      int  product = 1;
      for (int i = 1; i <= n; i++){

         product = product+1 ;
  }
      return product;
   }
 
   public static int combination(int n, int k)
   {
      int comb = squareNo(n);
 square(1);
      return comb;
   }
   public static int square(int n)
{
   int sq = 0;
   int spacesToSkip = 36; 
   for(int i=0;i<=9;i++)
{
sq =   i*i;
 
 
 
 
}

//i++;
 
   return sq;
}
 
    
   public static void main(String[] args) throws IOException
   {
      BufferedReader console = new BufferedReader(
 new InputStreamReader(System.in));
      int nrows;
      int n;
      int k;
      int comb;
      int spacesToSkip = 36; // spaces to skip at beginning of row
 
      System.out.println(
         "Enter the number of rows (<=13) in triangle:");
      nrows = Integer.parseInt(console.readLine());
      System.out.print("\n\n\n");
 
      // print the title
      System.out.println("THE FIRST " + nrows +       " ROWS OF TRIANGLE");
 
      for (n = 0; n < nrows; n++)
      {
         skip(spacesToSkip);
         spacesToSkip = spacesToSkip - 0;
 
         for (k = 0; k <= n; k++)
         {
            comb = combination(n,k);
            String out = "   " + comb;
            System.out.print(out.substring(out.length() - 4));
         }
 
         System.out.println();
         n++;
      }
   }
}
 

[A Kumar]

U can modify this...

public class Triangle {

public static void main(String[] args) {
int num=14; //u can make it as a user input
int val=0;
System.out.println(val);

int showval=2,count=1;

for(int i=1;i<= num; i++,count++){

val=(int)Math.pow(i,2);

if(count==showval){
showval++;
count=0;
System.out.println(val);
continue;
}

System.out.print(val + (val < 10 ? " ":val < 100 ?" ":" "));
}

}
}

System.out.print(val + (val < 10 ? "   ":val < 100 ?"  ":" "));        
  

[ August 10, 2005: Message edited by: A Kumar ]

[Stan James]

I'd look for something that expresses what we're doing as clearly as I could:

for ( row = 1; row <= rowcount; row++ )
{
   for ( col = 1; col <= row; col++ )
   {
      print( x squared )
      x ++
   }
   println("");
}

Your code dealt with leading spaces, but I don't see them in your sample output. If you want to right justify this thing:

          0
       1  4
    9 16 25
36 49 64 81

you might pick a line length & pad each line to that length before you print it.

// for each value in a line ...
line = line + rightJustify( Integer.valueOf( x squared ), 3 );
 
// at the end of the line
println( rightJustify( line, lineLength ));

You could figure the line length ... this kind of thing would be close enough to play with and fix up ...

largest x = ( number of rows squared ) / 2 + 1
longest x = length of ( x squared )
longest line = ( ( longest x + 1 ) * number of rows ) - 1

Any of that sound like fun?