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seeing id string has odd / even chars

dale con
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Joined: Apr 15, 2005
Posts: 93
hi all

i can find the length of a string

String s = "mystringodd";

can someone show me how i can then see if the string conains an even number of characters

e.g String s contains 11 chars

whati want to do is see if String s is even, if not i need to append a 0 to make it even, so string s becomes this 0mystringodd

can anyone help me ou with this


many thanks
Stan James
(instanceof Sidekick)
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Joined: Jan 29, 2003
Posts: 8791
If you have the length, look at the % arithmetic operator. That will give you the remainder from a division which you can use to see if length is even or not. If you're still stuck, post some code and we'll go from there.


A good question is never answered. It is not a bolt to be tightened into place but a seed to be planted and to bear more seed toward the hope of greening the landscape of the idea. John Ciardi
dale con
Ranch Hand

Joined: Apr 15, 2005
Posts: 93
thanks

i can get the remainder doing this

String s = "somestringvalue";

int n = s.length();

int remainder = n % 2;

but don't know how append String s with x number of 0's to make the String s even
Seb Mathe
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Joined: Sep 28, 2005
Posts: 225
if your length is odd, and then you add one char, your new length becomes even, no ?
[ October 18, 2005: Message edited by: Seb Mathe ]

Regards,<br />Seb<br /> <br />SCJP 1.4
Joel McNary
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Joined: Aug 20, 2001
Posts: 1817

Are you appending or prepending?

In either case, you have two basic choices: String concatenation or a StringBuffer.

String concatenation is simpler and, in this case, is more readable.


Note that Strings are immutable -- you can't change them, you can only create new strings based on them. (Of course, you can reassign a reference to point to a new String; you can say s = "0" + s;).

The StringBuffer alternative is best used when you are doing large blocks of concatenation.

[ October 18, 2005: Message edited by: Joel McNary ]

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