seeing id string has odd / even chars

[dale con]

hi all

i can find the length of a string

String s = "mystringodd";

can someone show me how i can then see if the string conains an even number of characters

e.g String s contains 11 chars

whati want to do is see if String s is even, if not i need to append a 0 to make it even, so string s becomes this 0mystringodd

can anyone help me ou with this


many thanks

[Stan James]

If you have the length, look at the % arithmetic operator. That will give you the remainder from a division which you can use to see if length is even or not. If you're still stuck, post some code and we'll go from there.

[dale con]

thanks

i can get the remainder doing this

String s = "somestringvalue";

int n = s.length();

int remainder = n % 2;

but don't know how append String s with x number of 0's to make the String s even

[Seb Mathe]

if your length is odd, and then you add one char, your new length becomes even, no ?
[ October 18, 2005: Message edited by: Seb Mathe ]

[Joel McNary]

Are you appending or prepending?

In either case, you have two basic choices: String concatenation or a StringBuffer.

String concatenation is simpler and, in this case, is more readable.

String s  = "somestringvalue";
String evenLengthString = "0" + s; // Prepending the 0
//Or
String evenLengthString = s + "0"; //Appending the 0

Note that Strings are immutable -- you can't change them, you can only create new strings based on them. (Of course, you can reassign a reference to point to a new String; you can say s = "0" + s;).

The StringBuffer alternative is best used when you are doing large blocks of concatenation.

String s = "somestringvale";
StringBuffer b = new StringBuffer(s);
b.insert(0, "0"); //Prepending the 0
//or
b.append("0"); //Appending the 0
String evenLengthString = b.toString();

[ October 18, 2005: Message edited by: Joel McNary ]