hi all, here is a problem while adding big decimal numbers.can anyone help me pls. double d1 = 999999999999.11; double d2 = 9.11; double d4 = (d1 + d2); System.out.println(" Adding big double numbers:::"+d4); // this will give me o/p as :: 1.00000000000822E12
but i am interested in getting the exact value. pls help me. thanks & regards, Mahesh
By the way, you mentioned the 'exact' value, technically d4 represents the exact value, it just displays in non-useful format. If you want to perform operations on the 'exact' value, you should still use d4. Only use the formatter to display the data on the screen to the user. [ November 09, 2005: Message edited by: Scott Selikoff ]
First, it's not possible to represent many fractions precisely in binary. Almost no computer languages or calculators will do this: (1 / 3) * 3 = 1. On the other hand most do (1 * 3) / 3 pretty well because there are no fractions involved.
Second, floats and doubles have two parts, sometimes called significand and exponent. The value is the significand times 2 raised to the exponent power. Since you get 8 or 11 bits of exponent you can multiply out some very large numbers. But the significand has only 23 or 52 bits so you can only have so many digits before you multiply. If you have more digits of precision than fit into those bits, some digits are lost.
Floats are good for the distance between galaxies or the size of an electron, but lousy for Bill Gates's checking account.
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