NumberFormatException and NumberFormat

[Sri Ram]

Hi Ranchers,
I was using NumberFormat for making the minimum integer digit to be 15. I encountered a NumberFormatException while converting back to Double.
Now my real Requirment is to enable some calculation for values more than 10 digits.
Here is the code. Where am i going wrong. Obviously the NumberFormat will give a value with like say "1,500,000,000,000,000" and when i convert this, i get NumberFormatException.

Now is there a method which will give me a Double value and also parsed value.

 
NumberFormat nm = NumberFormat.getInstance();
            nm.setMinimumIntegerDigits(15);
            Double dLoanAmount = Double.valueOf(sLoanAmount);
            String strLoanAmount = nm.format(dLoanAmount);
            System.out.println("strLoanAmount===============>"+strLoanAmount);
if(sLoanAmount!=""){
paymentplannerBO.setLoanAmount(Double.valueOf(strLoanAmount));
             System.out.println("strLoanAmount1===============>"+strLoanAmount);
            }

[Jeff Albertson]

Double.valueOf is not expecting a String containing commas.

But I think you need to think more about what you are doing. A Format object, like one of type NumberFormat is there to parse strings into numbers or format numbers as string, or both.

[Sri Ram]

Thanx Jeff, Still i am not able to figure out the solution.
Let me put it this way, I have a String which is a number of 15 Digits length. Now, I want to do some calculation on that, hence i am converting to a Double. Now it becomes 1.5E15. I cant do any calculation with this.
I want number as 1500000000000000. So what is that i have to do??

[marc weber]

Are you able to use BigDecimal or BigInteger?

Are you aware of the precision issues when using floating-point primitives?

[Sri Ram]

Hey marc. But i cant use BigDecimal or BigInteger. This is cause it would involve Huge Change in application level.

[marc weber]

Originally posted by Sri Ram:
...it becomes 1.5E15. I cant do any calculation with this.
I want number as 1500000000000000...

These are just different representations of the same quantity. Do your calculations. Then when you want to display a result, use the format method to give a nice-looking String representation.

[Sri Ram]

Originally posted by marc weber:

These are just different representations of the same quantity. Do your calculations. Then when you want to display a result, use the format method to give a nice-looking String representation.

Marc, I am passing the value to a third party API which accepts String.
The loanAmount goes as "1.5E15|GHB" where as i have to send "1500000000000000|INR".

Now when the API parses that value, its giving me an Exception. Hence i have to pass the value the same way i enter it in UI.

[Harshil Mehta]

Ram,

Marc, I am passing the value to a third party API which accepts String.
The loanAmount goes as "1.5E15|GHB" where as i have to send "1500000000000000|INR".

I don't think that the string "|GHB" in "1.5E15|GHB" is required. Is it so?

[Sri Ram]

Originally posted by Harshil Mehta:
Ram,



I don't think that the string "|GHB" in "1.5E15|GHB" is required. Is it so?

U see i have to pass Loan Amount along with its Currency. Hence thats very much mandatory. Thats y i am getting this problem. If its just double or value, i could have passed it without any problem.

[Jeff Albertson]

Two examples: each takes string "123456789012345", converts it to a number,
of some sort, doubles it and converts the result back to a string.

import java.math.*;
 
public class Test {
    public static void main(String[] args) throws NumberFormatException {
        String input = "123456789012345";
        System.out.println(computeUsingLong(input));
        System.out.println(computeUsingBigInteger(input));
    }
 
    public static String computeUsingLong(String input) throws NumberFormatException {
        return Long.toString(2*Long.parseLong(input));
    }
 
    public static String computeUsingBigInteger(String input) throws NumberFormatException {
        return new BigInteger(input).multiply(BigInteger.valueOf(2)).toString();
    }
}