charAt problem....

[Stephen Foy]

Keep getting an incomparable type error, i guess this is caused by my array?

public void solveTaskOne() {
for(int i = 0;i < 9;i++) {
for(int j = 0;j < 9;i++) {
if(blocks[i][j].length() == 1) {
for(int l = 0;l < 9;l++) {
for(int k = 0;k < 9;k++) {
String value = blocks[l][k];
for(int m = 0;m < blocks[l][k].length();m++) {
if(value.charAt(m) == blocks[i][j]) {
value.charAt(m) = " ";
}
}
}
}
}
}
}
}

Any ideas? thanks

[kalps ganvir]

check datatype of blocks array that u hav declared. if it isnt String then declare is as String. try out whether this works

[Jesper de Jong]

You didn't show the declaration of your array blocks[][], but this line:

String value = blocks[l][k];

suggests that it's a String[][] array.

Note that String.charAt() returns a char. You cannot compare a String to a char using ==, like you're doing here:

if(value.charAt(m) == blocks[i][j]) {

And this is not going to work:

value.charAt(m) = " ";

You cannot assign a value to a return value of a method like this, and also String objects are immutable. You'll need to do something like this:

blocks[i][j] = value.substring(0, m) + ' ' + value.substring(m + 1);

[Ke rem]

Yes Jesper is right. and

if(value.charAt(m) == blocks[i][j]) can be
if((int)value.charAt(m) == (int)blocks[i][j])

[Jesper de Jong]

Originally posted by Ke rem:
Yes Jesper is right. and

if(value.charAt(m) == blocks[i][j]) can be
if((int)value.charAt(m) == (int)blocks[i][j])

That last line is not going to work. blocks[i][j] is a String. You cannot cast a String to an int.

[Ke rem]

oops! Sorry.