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Loop gone wrong
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Wolfgang Obi
Ranch Hand
Joined: Dec 05, 2005
Posts: 134
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Hi can someone please tell me what I've done wrong in this programme.... the code seems to be okay, but the output is a bit faulty.... I'd really appreciate... Thx -W.O.
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marc weber
Sheriff
Joined: Aug 31, 2004
Posts: 11343
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The problem is with this segment of code: To see what's happening here, suppose the int 5 is input and assigned to zahl. Then... newZahl is 5. newZahl is 10. (This just adds newZalh to itself.) result1 is 10. (Supposedly a cumulative sum?) result2 is 1. (Supposedly an average?) Hint: Try describing exactly what you want to do in English before writing the Java code. For example, "I want to take the input number and add it to a cumulative total." [ April 26, 2006: Message edited by: marc weber ]
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"We're kind of on the level of crossword puzzle writers... And no one ever goes to them and gives them an award." ~Joe Strummer
sscce.org
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samir Sadiki
Ranch Hand
Joined: Apr 22, 2006
Posts: 31
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Hi You are in the right path, just try these minor changes public class sumAverage { public static void main(String [] args){ int newZahl=0; float result1 = 0; float result2 = 0; System.out.println("Please enter 10 Integers one by one and press [ENTER] after each entry!: " ); System.out.println(); for(int i=1; i<=10; i++){ System.out.print("What is your " +i+ ". integer?: " ); int zahl = IM.readInt(); System.out.println(); newZahl= zahl; //number enterd by the user //newZahl +=newZahl; get rid of this line result1 += newZahl; //the cumulative sum } result2 = result1/10; //once you've added all the numbers you can compute the average System.out.println("The sum is: " +result1 ); System.out.println(); System.out.println("The average is: " +result2 ); System.out.println(); System.out.println(); } }
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Wolfgang Obi
Ranch Hand
Joined: Dec 05, 2005
Posts: 134
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@Marc: that's a helpful hint! @Samir: thanx alot for the corrections! thanx guys,.... great help. -W.O.
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subject: Loop gone wrong
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