Short sh = new Short( 2); is indefined?

[Nikos Stavros]

I don't understand why in my code

   Short sh =  new Short(2); 

is indefined?

[Paul Sturrock]

Because there is no constructor in the Short class which takes an int value as a parameter. This will work:

short value = 2;
Short sh = new Short(value);

[Martin Simons]

well, Short can only be declared with a string or a short. Since a number
typed in the manner it is there is, per default, an integer, that
constructor is not defined. Fix in one of these two ways:

short a = 2;
Short b = new Short(a);
 
or
 
Short c = new Short("2");

[Nikos Stavros]

of course

thanks guys