How to convert ArrayList to String Array in java

[satheesh krishnaswamy]

Hi,
I try to convert an ArrayList into String Array.
I am getting "java.lang.ClassCastException:Class cannot be casted to array".
I am sure that the ArrayList is not Null.

I tried like this.

 
ArrayList formattedRows = AClass.aMethodName();//This returns correct
if(formattedRows.size >0)
{
for(int i=0;i<formattedRows.size();i++)
{
   System.out.println("Inside formattedRows loop");
        String[] row = (String[])formattedRows.get(i);
}
}

I am getting a ClassCast Exception.Kindly Help.

Its Pretty Urgent,Please

[Sunil Kumar Gupta]

Originally posted by satheesh krishnaswamy:
Hi,
I try to convert an ArrayList into String Array.
I am getting "java.lang.ClassCastException:Class cannot be casted to array".
I am sure that the ArrayList is not Null.

I tried like this.

 
ArrayList formattedRows = AClass.aMethodName();//This returns correct
if(formattedRows.size >0)
{
for(int i=0;i<formattedRows.size();i++)
{
   System.out.println("Inside formattedRows loop");
        String[] row = (String[])formattedRows.get(i);
}
}

I am getting a ClassCast Exception.Kindly Help.

Its Pretty Urgent,Please

Why dont you use toArray() method of ArrayList

String[] row = formattedRows.toArray();

[satheesh krishnaswamy]

Hey,
Thanks for the immedieate reply.

String[] name = formattedRows.toArray(); will give us an Object Array and not a String array.

However String[] name = (String[])formattedRows.toArray() will be fine.

But then,how will I get the values of name now.

My requirement is,

My ArrayList will contain multiple rows and multiple values.
like [a[1,2],b[3,4]]

I need to set 1,2,3 and 4 into individual Values in a Value Object.

How do I do this?

Please help.
from multiple rows I need to get

[Henry Wong]

My ArrayList will contain multiple rows and multiple values.
like [a[1,2],b[3,4]]

I need to set 1,2,3 and 4 into individual Values in a Value Object.

How do I do this?

Unfortunately, all the toArray() method does is to create an array where each element is a member of the arraylist. If a member of the list is another arraylist object, or array, it will simply be one element of the array.

I don't believe there is a short cut to do what you want. You will have to write some code that will iterate through the array list, check each member, and do any further iteration if necessary.

Henry