Overriding a method with Different Exceptions

[Pavan Chillara]

Hi,

I have written a class which would override a method in a super class,But super class method is throwing an ArithmeticException and method in sub class which will be overriding the above throwing an exception by name Exception.When i try to execute this it will be giving compilation error,But viceversa does not,
Can anyone explain the reason for this,The code is as follows

class A 
{
public int test() throws ArithmeticException
{
System.out.println("This is Class A");
return 0;
}
}
 

 

 
public class OverRidingEx extends A{

 

public int test() throws Exception
{
System.out.println("This is Class OverRidingEx");
return 0;
}

public OverRidingEx() {
super();
// TODO Auto-generated constructor stub
}
 

public static void main(String[] args) {
// TODO Auto-generated method stub
try
{
A a= new OverRidingEx();
a.test();
}
catch(Exception e)
{

}
 
}
 
}
 
Regards,
 

    

[pascal betz]

Hint:

ArithmeticException is a subclass of Exception and to be mroe precise it is a subclass of RuntimeException.


pascal
[ October 30, 2006: Message edited by: pascal betz ]

[Ernest Friedman-Hill]

When you override a method, you can declare the same exceptions, or some of them, or none of them; or you can declare subclasses of some or all of them. In other words, a subclass method can take away things from the superclass method's exception declarations, but it can't add anything. Your only choice is to catch all exceptions inside your subclass method and rethrow them as unchecked exceptions.