exception handling help

[Jason Mackie]

I am working on a project for my java class that has to do with exception handling. What i am trying to do is use a try catch block with multiple catches. when i run my program it just puts out an infinite loop. What it has to do is catch the InputMismatchException and then loop back to have the user retype two integers. I also have to define my own exception for dividing by zero...but that�s a question for later...please help...code below...thanks
----------------------------------------------------------------------------

import java.util.*;
public class Test 
{
   public static void main(String[] args)
   {
      Scanner scan = new Scanner (System.in);
      int n1, n2;
      double r1;
      boolean done;

      do
      {
         done = true;
 try
  {
            System.out.print("Please enter the first integer: ");
    n1 = scan.nextInt();
            System.out.print("Please enter the second integer: ");
    n2 = scan.nextInt();
    r1 = (double) n1 / n2;
    System.out.print(r);
         }
   catch (InputMismatchException e)
 {
    System.out.print("Please enter an Integer");
    done = false;
         }
      }
 while (!done);
   }
}

EDIT by mw: Added Code Tags.
[ February 07, 2007: Message edited by: marc weber ]

[Jason Mackie]

wow sorry about that...i had everything indented and everything...guess this forum didnt like it

[marc weber]

Originally posted by Jason Mackie:
...when i run my program it just puts out an infinite loop. What it has to do is catch the InputMismatchException and then loop back to have the user retype two integers...

Welcome to JavaRanch!

When the InputMismatchException is thrown, the Scanner does not advance, so it's still trying to scan whatever input caused the exception. To advance the Scanner past the "bad" input, try adding the following as the first line of your catch block...

scan.nextLine();

[Jason Mackie]

awesome thanks marc that worked...