Java operators

[Jackk Ripper]

Hi

I have this piece of code:
class Test {
public static void main(String s[]) {
int a = 1;

a = 2 + a + a++ + 3;
System.out.println(a);
a = 1;
a = 2 + a++ + 3 + a;
System.out.println(a);
}}

The output is:
7
8

Shouldn't the values be equal? I thought that values for all variables are first retreive. Then the unary operators are applied. Then lastly, the binary operators are applied from left to right. Please help.

Ripper

[Chandra Bhatt]

Hi Ripper,

Welcome to JavaRanch,

I have this piece of code:
class Test {
public static void main(String s[]) {
int a = 1;
a = 2 + a + a++ + 3;
System.out.println(a);
a = 1;
a = 2 + a++ + 3 + a;
System.out.println(a);
}}
 
The output is:
7
8

--> Left to right operation
a++, a is incremented after it is used.
int a=1;
a = 2 + a + a++ + 3;

a = a + 1 + 1 + 3=7;

(Simply understand in the way: You are assigning the resultant to the a itself, so incremented a goes lost)

a=1;
a = 2 + a++ + 3 + a;
a = 2 + 1 + 3 + 2=8;


Got it?

Regards,
cmbhatt

[marc weber]

"Jackk Ripper,"

Welcome to JavaRanch!

Please revise your display name to meet the JavaRanch Naming Policy. To maintain the friendly atmosphere here at the ranch, we like folks to use real (or at least real-looking) names.

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-Marc