posted 16 years ago
I am trying to use the combination rule of "n!/r!(n-r)!" but here is the pbm according to this if I wanted all the combinations for a particular number of pairs eg all two pair values ... eg 1, 2, 3, 4 the outcome would be (1,2) , (2,3) , (3,4) , (1,3) (1,4) , (2,4)
but I need all possible pairs say all 2 pairs, 3 pairs , 4 pairs etc... is it a good way to wrap it with a loop and pass the "r" value for each loop or is there a way to figure this out. Any help is highly appreciated.