Hi friends, i have some small doubt regarding in default value of char primitive type. Actually the default value of char primitive type is o, but when i am trying to print that value, its giving nothing. But when i am passing that in array as an index, its giving the value of a, if a is an array. I dont why it is showing like . can anybody tell me this and and clear this idea.
the default value of a char is not the character 'o' (lower case letter O), but the numeric value of 0 (zero). when you try and print it, java knows it's a char, so prints the ascii character associated with that number. if you look at an ascii table, you will see that the number 0 is a null character. it's a non-printing character.
There are only two hard things in computer science: cache invalidation, naming things, and off-by-one errors