multiple interface

[Jitendra Jha]

i have made 2 different interfaces which have the same method prototype(method declaration).when i implement both in a class,i see that they work fine.i want to know which method is used(from interface 1 or from interface 2)?how do i check?

package Dump1;

interface interfaceExp
{
int a=1;

void Name();

}


package Dump1;

interface interfaceExp1
{
int a=1;

void Name();

}



package Dump1;

class interfaceExpdemo implements interfaceExp,interfaceExp1
{
public void Name()
{
System.out.println("Hello");
}
public static void main(String args[])
{
interfaceExpdemo ied=new interfaceExpdemo();
ied.Name();
}
}

[Henry Wong]

i want to know which method is used(from interface 1 or from interface 2)?how do i check?

Unfortunately, there is no "which method" as there is only one implementation, that satifies both interfaces. From the method, there is no mechanism to tell what the reference type that was used to call the method was.

Henry

[pete stein]

and more importantly, it doesn't matter. The interfaces don't have any implementation, they are only a "contract" that the class that does implement the interface will have the contained method signature.

[Bear Bibeault]

Originally posted by pete stein:
and more importantly, it doesn't matter

Yet it may. If interface A expects method xyz() to do one thing, and interface B expects it to do another, the contract with one or other of the interfaces needs to be broken.

It doesn't matter as far as the compiler is concerned, but the situation is still one to be avoided.

[pete stein]

Originally posted by Bear Bibeault:
Yet it may. If interface A expects method xyz() to do one thing, and interface B expects it to do another, the contract with one or other of the interfaces needs to be broken.

It doesn't matter as far as the compiler is concerned, but the situation is still one to be avoided.

Thank you for that clarification.

[Jitendra Jha]

In the light of the above discussion,the question still remains,how do we know which method is being used.

[Bear Bibeault]

As there can be only one method, there is no amibiguity. What is ambiguous is which intention the method implements, which is why the situation shold be avoided.