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int data type takes 4 bytes

 
ramchander yshetti
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hai
int data type take 4 byte.

we can display max and min range of integer as
System.out.println(Integer.MAX_VALUE);
System.out.println(Integer.MIN_VALUE);

then
int i=10;

i want to print how many bytes for (int i=10) is allocated.
in C language we have sizeof() function to print.
Is there any method in java to print it.
 
Ulf Dittmer
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No. Java abstracts away that kind of low-level detail.
 
Kaydell Leavitt
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In Java, there is no need for a sizeof operator because in Java types are always the same size:

byte is always 1 byte
short is always 2 bytes
int is always 4 bytes
long is always 8 bytes

etc.

Kaydell
 
Jesper de Jong
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All that Java guarantees is that an int is 32 bits (4 bytes), so that you can store integer numbers with values between -2^31 and 2^31 - 1 in it.

If the JVM which you are using actually uses 4 bytes of memory, is something you don't know. On some computers it might for example take 64 bits because that's more efficient on that specific type of computer. However, if the JVM behind the scenes uses 64 bits, that doesn't mean you can suddenly store larger numbers in an int.

From the Java programmer's perspective, an int is always 32 bits. But how the JVM handles ints under water might be different.
[ August 02, 2007: Message edited by: Jesper Young ]
 
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