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int data type takes 4 bytes

ramchander yshetti
Ranch Hand

Joined: Apr 22, 2006
Posts: 97
hai
int data type take 4 byte.

we can display max and min range of integer as
System.out.println(Integer.MAX_VALUE);
System.out.println(Integer.MIN_VALUE);

then
int i=10;

i want to print how many bytes for (int i=10) is allocated.
in C language we have sizeof() function to print.
Is there any method in java to print it.
Ulf Dittmer
Marshal

Joined: Mar 22, 2005
Posts: 42916
    
  68
No. Java abstracts away that kind of low-level detail.
Kaydell Leavitt
Ranch Hand

Joined: Nov 18, 2006
Posts: 689

In Java, there is no need for a sizeof operator because in Java types are always the same size:

byte is always 1 byte
short is always 2 bytes
int is always 4 bytes
long is always 8 bytes

etc.

Kaydell
Jesper de Jong
Java Cowboy
Saloon Keeper

Joined: Aug 16, 2005
Posts: 14430
    
  23

All that Java guarantees is that an int is 32 bits (4 bytes), so that you can store integer numbers with values between -2^31 and 2^31 - 1 in it.

If the JVM which you are using actually uses 4 bytes of memory, is something you don't know. On some computers it might for example take 64 bits because that's more efficient on that specific type of computer. However, if the JVM behind the scenes uses 64 bits, that doesn't mean you can suddenly store larger numbers in an int.

From the Java programmer's perspective, an int is always 32 bits. But how the JVM handles ints under water might be different.
[ August 02, 2007: Message edited by: Jesper Young ]

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