Calculating Ln and exponent

[Ian Cockcroft]

Guys, I have two functions that need to return the ln of a parameter and the exponent of a parameter. How would I do this?

//d
public class A implements Function 
{
       public double apply(double x) 
       {
          return               //0.2ex;
       }
}
//e
public class B implements Function 
{
    public double apply(double x) 
     {
          return               //ln x;
     }
}

Thanks
Ian

[Stan James]

Ranchers don't generally do homework for you, unless maybe for a fee that would let me retire tomorrow. Are you stuck on the math algorithms? I'd just Google for those. Give it a shot and see if you can get something going!
[ August 02, 2007: Message edited by: Stan James ]

[Kaydell Leavitt]

The keyword to Google on is the "Math" class.

Kaydell

[David McCombs]

Originally posted by Kaydell Leavitt:
The keyword to Google on is the "Math" class.

Kaydell

Only if he is allowed to use the Math class, which it doesn't sound like it is permissible.. Besides Google isn't necessary, just go here.

[Jim Yingst]

If this is for a class, perhaps using a Taylor series would be appropriate for each. There may well be better ways to do this, depending on the desired domain of the functions, and how much effort it's worth to optimize speed. But that's where I'd probably start, assuming a Google search numeric approximations for eponentials and logarithms doesn't give you better ideas.

Of course if it's not for a class, then yes there's a much simpler solution suggested in earlier answers...