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How to get the path of property file.

Edward Durai
Ranch Hand

Joined: Oct 09, 2004
Posts: 223

I have one sample project named as TMS, In my "WEB-INF/conf" foler contains file. It contains

hostname = some host name
url= some url

This project contains only one file.
In java file, I want to get hostname and url from that property file.


Properties props=new Properties () ;
props.load ( new FileInputStream ( new File ("E:\\Workspace\\TMS\\WebRoot\\WEB-INF\\conf\\"))) ;

String host= "hostname";
String val = props.getProperty ("Host Name Is :"+ host ) ;

Using the above code, I have got both hostname and url.

But my problem is, How to get the current project file path.

Because in the above path name is hard coded.

So How we get current project file path?

Thanking you.

Thank You<br />Edward
Francois Dang Ngoc

Joined: Sep 02, 2007
Posts: 6
Hi Edward,

You can use the method getServletContext() as follows:

InputStream is = getServletContext().getResourceAsStream ("/WEB-INF/conf/");
Properties props = new Properties();
out.println("HOST: " + props.getProperty("host") + " URL: " + props.getProperty("url"));

Hope it helps,


Shane W
Ranch Hand

Joined: Aug 31, 2007
Posts: 30
How about using ResourceBundle?
You just need to know the property file name.

Apple Man
I agree. Here's the link:
subject: How to get the path of property file.
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