NumberFormatException

[Vijay Chandran]

    
class Test
{
     public static void main(String[] args)
     {
         String str = "12121211193148935244";
         Long a  = Long.valueOf(str);
         System.out.println("a: " + a);
      }
}

Dear friends,
This code is giving me NumberFormatException. I want to convert that String value to a Long/long data type.
long a = Long.parseLong(str) also gives me NumberFormatException.

Kindly help me out to solve this problem.
Regards,
Vijay

[Paul Sturrock]

The number looks suspiciously like its a larger value than a long can hold. Have a look at BigInteger.
[ October 23, 2007: Message edited by: Paul Sturrock ]

[Rob Spoor]

A long can only store numbers up to 9223372036854775807. Your number is larger than that, so it won't fit in a long. That's the reason of the exception.

Compare:
9223372036854775807 vs
12121211193148935244

You'll need either a float or double, or java.math.BigInteger.

[Vijay Chandran]

Thank you very much for the reply.

I am getting the value as a String.

How can i check that such a big value can be an integer or BigInteger.

Regards,
Vijay

[Nitesh Kant]

Originally posted by vijaychandran rajagopalan:

How can i check that such a big value can be an integer or BigInteger.

Why not always use a BigInteger when you suspect that the value *can* be big.