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Postfix vs Unary..

 
Jay Taylor
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I want to make sure I understand this.
class Sequen
{
public static void main(String args[])
{
int a = 2;
int b = 7;

int e = 2;
int f = 7;

int c = a *++b;

int d = --e *f;// This will case d to equal 7
int d = e-- *f;// This will cause d to equal 14

System.out.println(c);
System.out.println(d);
}
So the question is.. Will my Unary not be calculated in these problems? How can I cause the Unary to decrement from the int prior to the calculation?
}
 
fred rosenberger
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well...

first, this code won't compile. you have declared 'd' twice. assuming you fix that (I made the second one a 'g'), your assumption of what d/g becomes is wrong. Here is my code:

here is the output:

C:\slop>java -cp . Sequen
16
7
7

C:\slop>


so, your second comment is wrong. when we hit the "d = --e * f" line, originally e is 2, and f is 7.

the pre-increment operator says "ok, decrement e FIRST - that makes e equal to 1. NOW finish the line... so 1 * 7 is 7".

Then we come to "g = e-- * f". When we get here, we say "ok, i have a post-fix operator. So, get the value of e, which is 1. I'll remember that, and increment e, making it 2. Using that value I remember, finish the line. I remember e was 1, so multiply that by 7, so I set g to 7".
[ February 04, 2008: Message edited by: Fred Rosenberger ]
 
Jay Taylor
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Let me re-word my question... I failed to comment out a line last time or to fully explain my question. Sorry.

Why does g=14 in the code below?

class Sequen
{
public static void main(String args[])
{
int a = 2;
int b = 7;

int e = 2;
int f = 7;

int c = a *++b;

//int d = --e *f;

int g = e-- *f;

System.out.println(c);
//System.out.println(d);
System.out.println(g);
}
}
 
fred rosenberger
lowercase baba
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Jay,

Please start using the 'code' tags when you post code. it preserves the formatting, and makes your code easier to read. you can click the litle "Instant UBB Code" buttons below where you enter your text to have them pop in, then paste your code between them.

Second, you may want to read some of these, in particular the 'isolate the details' and 'avoid red herrings'. For code as small as this, it's not a big deal, although you would have gotten an answer faster if you had been more clear in your original post.

I'm not trying to be mean at all - i'm trying to help you use our site better.

now, to answer your question. Let's chop out all the stuff that doesn't matter:


So, why is g 14, you ask? when we get to the assignment, java runs like this:

"ok, 'e' has a post-fix decrement operator. So, i need to FIRST figure out what e is - that's 2. i'll remember that, since i'll use it later. now i need to decrement e by one, making it 1. Ok, now i need to multiply that value i remember by whatever 'f' is - 7. So, i remember that value was 2, and 2 * 7 is 14."
 
I agree. Here's the link: http://aspose.com/file-tools
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