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identifier name
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Ajay Kumar Rana
Greenhorn
Joined: Feb 27, 2008
Posts: 13
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Hi, I have typed this statement in eclipse char \u0061 = �a�; and it is not giving any error . But it has to give error because the identifier name is starting with "\" which is illegal, please give me explanation about this identifier naming.
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Amir Alagic
Ranch Hand
Joined: Mar 21, 2006
Posts: 65
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http://java.sun.com/docs/books/tutorial/java/nutsandbolts/variables.html http://java.sun.com/docs/codeconv/html/CodeConventions.doc8.html
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Jesper de Jong
Java Cowboy
Bartender
Joined: Aug 16, 2005
Posts: 12928
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I think Ajay already understands what characters you can use in a variable name. In Java source code, you can use Unicode escape sequences that look like \uNNNN where NNNN is the four-digit hexadecimal code of the character. These escape sequences are processed by the Java compiler as the very first step in the compilation process. Because of this, you can use an escape sequence in the place of a normal character. Character 0061 is the lower case a. So char \u0061 = 'a'; is exactly the same as: char a = 'a'; You could even go further. Do you understand what the following line of code is? \u0063\u0068\u0061\u0072\u0020\u0061\u0020\u003d\u0020\u0027\u0061\u0027\u003b [ February 28, 2008: Message edited by: Jesper Young ]
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Java Beginners FAQ - JavaRanch SCJP FAQ - The Java Tutorial - Java SE 7 API documentation
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subject: identifier name
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