Clarification on using increments

[Keshan Pillay]

          int x = 10;
int y = 20;
int z = 15;
 
x = y++;
y = x++;
z = z++;
 
System.out.println("x:" + x);
System.out.println("y:" + y);
System.out.println("z:" + z);  

That a fragment of code I had in an exercise recently.
It gives the output:
x:21
y:20
z:15

I can't seem to work out why this is. Could anyone please explain this to me?

[amitabh mehra]

x++, y++, z++... these are post increment operator

[ May 22, 2008: Message edited by: amitabh mehra ]
[ May 22, 2008: Message edited by: amitabh mehra ]

[amitabh mehra]

u can take a look PostIncrementOperatorAndAssignment

[Mala Gupta]

Keshan

Revisit the following lines of code:

Line1> int x = 10;
Line2> int y = 20;
Line3> int z = 15;

Line4> x = y++; // Values of x and y, AFTER the execution of this line of code: x=20, y=21
Line5> y = x++; // Values of y and x, AFTER the execution of this line of code: y=20, x=21
Line6> z = z++; // Value of x and y, AFTER the execution of this line of code: z=15

For lines 4 and 5, please note that when a postfix increment operator is used, the value of the variable is used before its value increments.

For line 6, the value of z will not change. Please refer to the following link for more information on this topic:

http://faq.javaranch.com/java/PostIncrementOperatorAndAssignment

cheers
Mala

[Campbell Ritchie]

Originally posted by amitabh mehra:
u can take a look PostIncrementOperatorAndAssignment

Please use real words, not "u" Some people didn't grow up with English, or use translation software, and they cannot understand "u". UseRealWords
[ May 22, 2008: Message edited by: Campbell Ritchie ]

[Keshan Pillay]

Thank you very much for your help, I understand how it works now. ^_^