loss of precision error

[Puneet N Vyas]

when we compile this it gives possible loss of precision which is obvious,but why this same code runs in other language c/c++,i run it on linux based gcc compiler,can any one tell why this happens

    
public class test1
{
public static void main(String args[])
{
char c = 'c'; int i = 10; double d = 10; long l = 1; String s = "Hello";
s=s+i;
c=(c+i);
System.out.println(c);
}
}
 

[Ronald Schild]

It compiles in other languages because there are differences between java and say, c++.

However, with c=(c+i) you assign an integer to a char which is a downcast that you need to make explicit.

All numbers are implicitly widened to an int when used in a calculation. The result is also at least an int.