Question regarding println statement

[Arjun Reddy]

Hi all,

Why does the first println statement in the following code works and the other does not? Is it because in the first println statement, 12 is actually converted to a string? and in the second println statament, bye is considered as some variable that has not been initialized something? please explain.

public static void main(String[] args) {

System.out.println("hi" + 12);//This works
System.out.println("hi" + bye);//This does not work??
}

Thanks.

[Campbell Ritchie]

Yes, because you haven't declared or initialised "bye." Actually the 2nd println statement won't compile, it would work if bye existed.

[Arjun Reddy]

Thanks.

[Campbell Ritchie]

You're welcome.