i need some other logic

[tulasi reddy]

My Requirement is

public String MethodName(String query, List listValues)
{
//Here your code

}

There should be a test method i.e main in the class you are going to create
Tasks to be done:
1.Query =" VouchNumber='~VouchNum~' AND BusinessUnit='~BU~' AND InvoiceNumber='~IN~' "
HashMap will contain key value pair all strings VouchNum=00005, BU=0231,IN=3443

Output should be :

" VouchNumber='00005' AND BusinessUnit='0231' AND InvoiceNumber='3443' "

I have done like this

import java.util.*;
import java.lang.*;
class TestHashMap
{
public static void main(String[] args)
{
 
String query1 =" VouchNumber='~VouchNum~' AND BusinessUnit='~BU~' AND InvoiceNumber='~IN~' ";
 
List lstOne = new ArrayList();
 
lstOne.add("00005");
lstOne.add("0231");
lstOne.add("3443");
 
TestHashMap t = new TestHashMap();
String output = t.data(query1, lstOne);
 
System.out.println(output);
}
 

public String data(String query, List listValues)
{
HashMap map = new HashMap();
 
map.put("VouchNum", listValues.get(0) );
map.put("BU", listValues.get(1));
map.put("IN",listValues.get(2 ));
 

String vNum = (String) map.get(0);
String bUnit = (String) map.get(1);
String inVc= (String) map.get(2);
 
/** use string buffer for better perfomance */
StringBuffer result = new StringBuffer();
 
if (vNum!=null && vNum.length()>0)
{
result.append("VouchNumber='");
result.append(vNum);
result.append("' AND ");
 
}
 
if(bUnit!=null && bUnit.length()>0)
{
result.append("BusinessUnit='");
result.append(bUnit);
result.append("'");
 
}
 
if(inVc!=null && inVc.length()>0)
{
result.append("InvoiceNumber='");
result.append(inVc);
result.append("'");
 
}
 

return result.toString();
 
}
 
}

can you just check the code.let me know what are the changes to be done.
or can i use some other logic.

with regards,
Tulasi.

[Joanne Neal]

The Search logic might help. This is at least the third post asking for help on this question.

[Rob Spoor]

Which means that either someone is using multiple accounts, or this is a homework assignment.

Anyway, this thread already has been handling this topic.

[Campbell Ritchie]

Several people on the same course. The person who has got the farthest has been given an additional related assignment which seems even more difficult.