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parseInt throwing exception

prav ba
Greenhorn

Joined: Jun 17, 2007
Posts: 12
hi all,
am doing something really simple (at least looks simple to me) but i get a java.lang.NumberFormatException: For input string: "70611111111111111111111111111111111111"

all my code does it try and parse a string, does this error mean the integer value of the string passed in is too big ??

code: java.lang.Integer.parseInt(str);


thanks.
Steve Luke
Bartender

Joined: Jan 28, 2003
Posts: 4181
    
  21

Yup, number is too big. You might try using instead.


Steve
Campbell Ritchie
Sheriff

Joined: Oct 13, 2005
Posts: 38840
    
  23
It's always worth looking in the API dopcumentation.
Jesper de Jong
Java Cowboy
Saloon Keeper

Joined: Aug 16, 2005
Posts: 14150
    
  18

An int in Java is 32 bits, and is stored in two's complement format.

Because of this, the largest positive value that you can store in an int is 2^31 - 1 = 2147483647


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