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java.security.AccessControl Exception

 
malvika Pandit
Greenhorn
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Hi all,

I am writing an applet that communicates with a servlet.
My program works fine when I run on local host. However when I run on remote machine by giving its IP address in applet.It gives following error

java.security.AccessControl Exception access denied(java.net.socket permission 192.168.1.39 conect,resolve)
here 192.168.1.39 is the IP address of remote client on LAN.
I changed the java.policy file socketpermission to all listen,connect,accept,resolve. But the problem remains same.
Whats the solution for this?
I use tomcat server(8080 port)
Please help.
 
Ulf Dittmer
Rancher
Posts: 42967
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Where did you change the policy file - on the machine where the applet fails to run? Make sure there aren't several JREs installed on that machine; this happens frequently, and the applet may be run with a different JRE than the one you changed the security policy for.
 
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