Map instantiate with key-value

[nimo frey]

How can I do this in one line?

Map<String, List<String> :wink:  myMap=  new HashMap<String, List<String>>();
myMap.put("myKey", myList);

Something like:

Map<String, List<String> :wink:  myMap=  new HashMap<String, List<String>>(myList);

[Christophe Verré]

Unless I'm missing something obvious, the API does not allow you to do it. Is it bothering you to put it in different lines ?

[Sherif Shehab]

Originally posted by Christophe Verre:
Unless I'm missing something obvious, the API does not allow you to do it. Is it bothering you to put it in different lines ?

Hi , i think Christophe is right API doesn't allow this check this for more deatils

[Rob Spoor]

You can create an anonymous subclass with an initializer block:

Map<String, List<String>> myMap = new HashMap<String, List<String>>()
{
    {
        put("myKey", myList);
    }
};

I wouldn't do that though, since a) it's confusing, and b) it's longer than just calling the put methods.

[Christophe Verré]

I wouldn't call Rob's trick to be one line long

[nimo frey]

okay thanks.

It does not matter, I was just wondering, if it would be possible with anonymous declarations or the like.

thanks

[Rob Spoor]

Originally posted by Christophe Verre:
I wouldn't call Rob's trick to be one line long

But it can be; just remove all the enters

Map<String, List<String>> myMap = new HashMap<String, List<String>>() { { put("myKey", myList); } };

This is actually similar to how .NET 3.0 and up handle object initialization; the inner bracket pair is removed but the rest is the same.