Problem in StringTokenizer

[Meet Gaurav]

Am trying to split the String as (^) Separeted. Even I tryed Split method also..Any Other Way to split this one.. Please assist Me

public static void main(String[] args) 
{

String messStr = "A(^)B|#|TE^ST|#|BCF^ll(^)";
StringTokenizer st = new StringTokenizer(messStr, "(^)"); 
while(st.hasMoreTokens()) 
System.out.println(st.nextToken()); 
}
OutPut
------
A
B|#|TE
ST|#|BCF
ll
 
Expected Ouput
--------------
A
B|#|TE^ST|#|BCF^ll
 

I seen the String Tokenizer class they were charAt method for searching. This may be a reason for my problem.

Regular Expression is the only Option
[ November 03, 2008: Message edited by: Meet Gaurav ]

[Campbell Ritchie]

Look closely at what you are separating on; you are getting exactly what you have requested.
And please use String#split rather than StringTokenizer, as explained in the API.

[Meet Gaurav]

HI Campbell Ritchie,

I was not able to split the string using Split(). Could you please assist me with the above example. I want (^) separated

[Meet Gaurav]

I tryed and finally I got this.. For the above example the beloew code splits the string to (^) separeated..

String delimeter = "\\(\\^\\)";
temp = str.split(delimeter);
for(int i =0; i < temp.length ; i++)
System.out.println(temp[i]);

[Campbell Ritchie]

Sorry, I was confused about what you wanted to split on.
But using StringTokenizer, if you look through the constructor details, it appears to use any part of the delimiter to split. So it can split on ( or ) or ^ or (^ or ^) or (^).
You have found out (well done ) how to get the whole pattern into a regular expression.

[Martijn Verburg]

Thanks for posting your solution for others to share!

[Meet Gaurav]

how to get the whole pattern into a regular expression. ??? Am not getting this one..

This is my actual Code to split the strings to "(^)" separated
( - Special Character. So i need to add "/". And the slash is also a special character. so I need to add 1 more "/". And thats it.

String[] temp = str.split("\\(\\^\\)");
for(int i =0; i < temp.length ; i++)
System.out.println(temp[i]);

[Martijn Verburg]

I'm not sure what your question is here? The pattern you have provided is correct.