doubt in -cp option....

[Ganeshkumar cheekati]

My working directory structure is :\java\scjp\c-1
CODE:1

package pack1;
public class Cp1
{
}

I have compiled the above code by using command
D:\java\scjp\c-1>Javac -d C:\ Cp1.java
Cp1.class file is created under package pack1 in C:\

CODE:2

package pack2;
import pack1.*;
class Cp2
{
public static void main(String[] a)
{
Cp1 c=new Cp1();
System.out.println("yeah i got it:");
}
}

I have compiled the above code with command
D:\java\scjp\c-1>javac �cp C:\ n �d . Cp2.java
I got Cp2.class file under package pack2 in my current working directory�..

I run Cp2 with command
D:\java\scjp\c-1>java �cp C:\;. pack2/Cp2
I got output as �yeah I got it���.


CODE:3

import pack1.*;
import pack2.*;
class Cp3
{
public static void main(String[] a)
{
Cp1 c1=new Cp1();
Cp2 c2=new Cp2();
System.out.println("SUCCESS:");
}
}

I am compiling this code with command:
D:\java\scjp\c-1>javac -cp C:\;. Cp3.java

Then it is showing compilation error as:

Can not access Cp1
Bad class file:C:\Cp1.java
File does not contain class Cp1
Please remove or make sure it appears in the correct subdirectory of the classpath.
Cp1 c1=new Cp1();
^
1 error

Is there any mistake in command?
How can I compile the above code?

[Ankit Garg]

Ganesh you should keep the source files in the folders of their corresponding packages. It is not compulsory but if don't do that, and while compiling a file, if it finds a .java file in the wrong directory i.e. not in it's package directory, then it starts showing error. I don't know the exact mechanism, but you problem will be solved if you make this hierarchy

c:\folder
  |
  |-Cp3.java
  +pack1
  |  |-Cp1.java
  +pack2
     |-Cp2.java

Now if you have not set the classpath, and if it is set and it includes a dot (.) in it, then just move to the directory folder and then use the command

javac Cp3.java

then all three files will get compiled...