xslt String replace with node

Hi
I am trying to format Strings (like Java formatter) using xslt
so the outoput will be replaced with the matching {X} in the string of the data section
for example xml :

the desired output will be:

No param
Hallo world Steve and Hi roman
Hallo bla bla world roman and Hi vss

I am able to replace just normal strings with a tamplate, but i am unable to replace regular expressions

sample xsl:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    version="2.0" exclude-result-prefixes="#all">
 
<xsl:template match="/">
  <html>
  <body>
    <h2>Test substitution</h2>
    <table border="1">
      <tr bgcolor="#9acd32">
        <th>New Text: </th>
      </tr>
 
      <xsl:for-each select="page/data/str">
      <tr>
        <td>
<xsl:call-template name="format-literal-content-helper">
      <xsl:with-param name="text" select="."/>
  </xsl:call-template>
 </td>
     </tr>
      </xsl:for-each>
    </table>
  </body>
  </html>
</xsl:template>

<xsl:template name="format-literal-content-helper">
   <xsl:param name="text"/>
   <xsl:variable name="regExp" select="'{[1-9]}'"/>
   <xsl:choose>
      <xsl:when test="contains($text,$regExp)">
         <xsl:value-of select="substring-before($text,$regExp)"/>
         <br/>
         <xsl:call-template name="format-literal-content-helper">
            <xsl:with-param name="text" select="substring-after($text,$regExp)"/>
         </xsl:call-template>
      </xsl:when>
      <xsl:otherwise><xsl:value-of select="$text"/></xsl:otherwise>
   </xsl:choose>
</xsl:template>
</xsl:stylesheet>

Is it possible to contain function to get regex?
Thank you

So what happens instead? You get those nodes, unchanged, in your output?

Are you using a transformer which can handle XSLT 2.0?

Originally posted by Paul Clapham:
So what happens instead? You get those nodes, unchanged, in your output?

I am able to replace Strings and i get the correct output for string replacemant, but i cannot find "{[0-9]}" as regex.
for example, in the attached xsl if you replace the line:
<xsl:variable name="regExp" select="'{[1-9]}'"/>
with :
<xsl:variable name="regExp" select="'ReplaceMe'"/>

all "ReplaceMe" word in the input will be replaced.

Are you using a transformer which can handle XSLT 2.0?
Yes.

[ November 23, 2008: Message edited by: Sharon whipple ]

Hi Sharon. The contains and substring- functions don't use regular expressions. You'll need to use the matches and replace functions, or xsl:analyze-string and its related instructions.