This week's book giveaway is in the OO, Patterns, UML and Refactoring forum. We're giving away four copies of Refactoring for Software Design Smells: Managing Technical Debt and have Girish Suryanarayana, Ganesh Samarthyam & Tushar Sharma on-line! See this thread for details.
hi, i made a struts application..when i do POST or GET to my actionservlet and it forwards the view to other page using findForward()..in browser it will still show the URL to which i did POST/GET. i want to update it with my latest view...how can i do that? For example.. in my login.jsp page i entered my userid and password and hit enter which has a ACTION='/loginaction.do' in the form. after the successfull login of failed login it will show in browser URL as http://localhost:8080/loginaction.do in browser but i want this URL to be updated with my current view which is one the two http://localhost:8080/loginfailed.jsp or http://localhost:8080/loginsuccess.jsp any suggestion???
i knw it happens because of requestDispacher. its same with the case when someone from servlet does it using requestDispacher. it will still show the address of servlet in place of jsp to which i forwarded...any suggestion for that???
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But how do i use that in struts?? struts has to return using findForward() method in execute method....so where do i use that?? do you want me to put this before return statement??? then what would be the use of <forward > tag inside <action>mapping tag?? that is useless then....how to do this with a actionSErvlet in struts tell me...pplz