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BufferedWriter for Mulitple file type

Myat Thu
Greenhorn

Joined: Dec 10, 2008
Posts: 7
Hi All,

I want multiple files to upload to Web(or)FTP Server.
So, now what i have been done is
i carried whichever files and wherever location from client browser to servlet file.
Here is my servlet code.

My problem is i don't know how to write multiple file to server.
If i need to use BufferedWriter to write multiple file, how should i do.
I want to write not just single file, i need to write multiple files and mulitple files type.
Please give me suggestion.

public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException{

try{
boolean isMultipart = ServletFileUpload.isMultipartContent(request);
if (!isMultipart) {
} else {
InputStreamReader input = new InputStreamReader(request.getInputStream());
BufferedReader buffer = new BufferedReader(input);

String line ="";
do{
line = buffer.readLine();
System.out.println("Multipart data " + line );
}while(line != null);
}
}catch(Exception e){
e.printStackTrace();
}

}

Here is my console output.

10:03:29,390 INFO [STDOUT] Multipart data -----------------------------7d85d1d7027c
10:03:29,390 INFO [STDOUT] Multipart data Content-Disposition: form-data; name="txtFile1"; filename="D:\TestForUpload\Phrase1.txt"
10:03:29,390 INFO [STDOUT] Multipart data Content-Type: text/plain
10:03:29,390 INFO [STDOUT] Multipart data
10:03:29,390 INFO [STDOUT] Multipart data Form-based File upload in HTML is defined in RFC 1867.
10:03:29,390 INFO [STDOUT] Multipart data The enctype attribute of the form element in HTML specifies the content
10:03:29,390 INFO [STDOUT] Multipart data type of the data submitted to the server.
10:03:29,390 INFO [STDOUT] Multipart data The default encrypt type is application/x-www-form-urlencoded .
10:03:29,406 INFO [STDOUT] Multipart data This content type is not efficient for forms containing non-ASCII data,
10:03:29,406 INFO [STDOUT] Multipart data binary data or files. In such case, the encrypt type multipart/form-data is used.
10:03:29,406 INFO [STDOUT] Multipart data A typical HTML form for file upload looks like:
10:03:29,406 INFO [STDOUT] Multipart data -----------------------------7d85d1d7027c
10:03:29,406 INFO [STDOUT] Multipart data Content-Disposition: form-data; name="txtFile1"; filename="D:\TestForUpload\Phrase2.txt"
10:03:29,406 INFO [STDOUT] Multipart data Content-Type: text/plain
10:03:29,406 INFO [STDOUT] Multipart data
10:03:29,406 INFO [STDOUT] Multipart data Once the form is submitted, the binary multipart form-data is available in the HttpServletRequest
10:03:29,406 INFO [STDOUT] Multipart data as an InputStream. The regular form data are not available as Parameter and
10:03:29,406 INFO [STDOUT] Multipart data request.getParameter(?hsubmit?h) will always return null. So for any data submitted,
10:03:29,406 INFO [STDOUT] Multipart data you will have to know the content and then retrieve the content by parsing through the stream:
10:03:29,406 INFO [STDOUT] Multipart data -----------------------------7d85d1d7027c
10:03:29,406 INFO [STDOUT] Multipart data Content-Disposition: form-data; name="txtFile1"; filename="D:\TestForUpload\Phrase3.txt"
10:03:29,406 INFO [STDOUT] Multipart data Content-Type: text/plain
10:03:29,406 INFO [STDOUT] Multipart data
10:03:29,406 INFO [STDOUT] Multipart data You can write a parser yourself to analyze each multipart data from the stream and grab it
10:03:29,406 INFO [STDOUT] Multipart data as they apply to your application. There are some good ones already written.
10:03:29,406 INFO [STDOUT] Multipart data Apache has a Commons Fileupload Library, now let?fs see how we can use it to upload files.
10:03:29,406 INFO [STDOUT] Multipart data -----------------------------7d85d1d7027c
10:03:29,406 INFO [STDOUT] Multipart data Content-Disposition: form-data; name="txtFileOther"; filename=""
10:03:29,406 INFO [STDOUT] Multipart data Content-Type: application/octet-stream
10:03:29,406 INFO [STDOUT] Multipart data
10:03:29,406 INFO [STDOUT] Multipart data
10:03:29,406 INFO [STDOUT] Multipart data -----------------------------7d85d1d7027c--
10:03:29,406 INFO [STDOUT] Multipart data null
William Brogden
Author and all-around good cowpoke
Rancher

Joined: Mar 22, 2000
Posts: 12803
    
    5
Important note:
Once the form is submitted, the binary multipart form-data


You need to read and write a binary stream - NOT a character stream.

Reader and Writer io always attempts to interpret a stream as characters which is bound to cause trouble.

Bill
 
I agree. Here's the link: http://aspose.com/file-tools
 
subject: BufferedWriter for Mulitple file type