I'm trying to do something that I thought would be common and trivial, but after hours of googling, appears to be neither. Basically, I am simply trying to determine whether a given String represents a valid integer (or decimal, in some cases) for a given locale.
First, I checked simply to see if methods like Integer.parseInt() accept a Locale; they do not. Then, I thought I could retrieve the decimal-separator and group-separator (e.g. a comma--as in 1,000--in the US) from either the Locale or the NumberFormat object and do my own validation of the String, but I cannot retrieve that information either. So finally I decided to try a brute force approach just try to parse the String and if it works, the String is valid, and if an Exception is thrown, it is not valid:
But it turns out that you can pass pretty much any String in, and the NumberFormat will force it into a number. Seriously, "1asdsad" successfully converts to 1.
My last option, I guess, is to simply parse the String and validate that every character is either a number, or '.', '\'', ' ', or ','. But that hardly seems accurate, and would cause a lot of false negatives. So I think I must be missing something. What I'm trying to do has got to be commonplace, but I can't find any examples anywhere.
Does anyone know of a proper approach?
Thanks in advance.
Dave Taubler<br />Specializing in <a href="http://taubler.com/articles/" target="_blank" rel="nofollow">Java and Web Development</a>
author and iconoclast
You're really close. You can use the version of NumberFormat.parse() which takes a ParsePosition as the second argument. When parse() returns, check to see if theParsePosition.getIndex() == theString.length(); if it is, the parse accepted all the characters.