Hello Ranchers,
In our application,the datatype 'double' has been used for monetary transaction,now there is a calculation of adding two fares,the result is not quite correct.

For Ex: sum of 185.70 , 642.20 gives 827.9000000000001, but that is not correct, it should be only 827.90

Agree about BigDecimal. For that transaction try . . . new BigDecimal("185.70").add(new BigDecimal("642.20"));
Note the "" because you can get errors passing doubles to the BigDecimal constructor. Better to pass Strings instead.

We have a page of FAQs: look at no 20, which will provide much more information.

An alternative approach is to multiply all your prices by 100 and us integer arithmetic.

Ramna Reddy
Ranch Hand

Joined: Aug 06, 2006
Posts: 96

posted

0

Thank you guys,

To avoid the above the problem,now I have to convert 'double ' values to BigDecimal, I would like to know,if converting double to bigdecimal and again bigdecimal to double,would result any bad effects..I mean any truncation takes place.

For Ex;
static Double getTotal(){
Double dTotal = new Double(0.0);//suppose this is existing
BigDecimal bTotal = new BigDecimal(Double.toString(dTotal));// I want to change like this

//calculation
//dTotal += anObject.getTotal(); // let's say existing as above
bTotal = bTotal.add(new BigDecimal(anObject.getTotal().toString()));// new change..here anObject.getTotal() returns double value

dTotal = bTotal.doubleValue();

return dTotal;
}

Campbell Ritchie
Sheriff

Joined: Oct 13, 2005
Posts: 38726

23

posted

0

Depends on the actual values in the BigDecimal. BigDecimal will happily support values like 123456789.10111213141516171819, which would be badly truncated if you change it to a double. I can see no point in mixing double and BigDecimal arithmetic; stick to BigDecimal, but remember you have to specify the rounding mode if you divide.
And you may not need "new BigDecimal(0.0);" there is (I think) a value ZERO in the BigDecimal class already set up.

There was more discussion about a similar problem recently, here.