Method Variable

[david john]

Hi, In the below mentioned code, value of x and y is printed as 3 and 7. I have a doubt, as I understand scope of variable used in the method is only till the method exists. Once the method is finished variable used in method will also not exist. Why in this case method variable is overwritting the class variable?

   
class Example {
int x=50;
int y=100;
public static void main (String args[]){
int x=0, y=10;
Example ex = new Example();
while (x<3) {
x++; y--;
}
System.out.println("x=" +x+", y="+y);
}
}

 

Thanks in advance for your help!!!

[Rob Spoor]

If you indent your code properly you will immediately see why:

class Example {
    int x=50;
    int y=100;

    public static void main (String args[]) {
        int x=0, y=10;
        Example ex = new Example();   
        while (x<3) {
            x++; y--;   
        }   
        System.out.println("x=" +x+", y="+y);   
    }
}

Now look closely at the print statement: which x and y does it actually print?

[amitabh mehra]

david john wrote:... I have a doubt, as I understand scope of variable used in the method is only till the method exists. Once the method is finished variable used in method will also not exist...

You yourself have answered it
When you are printing the x and y in the main method, its the local variables not the other ones.

[david john]

Silly of me.... Did not see that... thanks a lot...