command line arguments

[ye zeya]

Dear ALL..
I am a very beginner to Java and now learning it.Here some little point I want to know clearly.

class readArgs{
	public static void main(String args[]){
        int i;
		for(i=0;i<args.length;i++){
			System.out.println(args[i]);

		}
	System.out.println("The Number of Arguments = "+i);
	}
}

[edit]Add code tags. CR[/edit]


I made the above program but have error.The idea is to accept the command line arguments and display how many arguments are there.
I can make it by the following alternative way.However..I also would like to know why question for my first program.
Thank you..">

[Vikas Kapoor]

Hello Ye,

Welcome to JavaRanch!

I made the above program but have error

I can successfully compile and run it at my end. What error is that?

[Campbell Ritchie]

Welcome to JavaRanch
Please use the CODE button; I have edited your original post so you can see how much better it looks.

campbell@linux-747u:~/java> java readArgs Campbell Ritchie Ye Zeya
Campbell
Ritchie
Ye
Zeya
The Number of Arguments = 4

I can see no errors; please supply more details of your problem.

[ye zeya]

Arr....Sorry for my childish carelessness. I compiled the program with wrong name readArgs2 in stead of renaming the former program readArgs.java .So the main class does not match the file 's name . .Really sorry for my fault.
Thank you for your kind helps.Next time I will try to avoid such funny mistakes.

[Vikas Kapoor]

NeverMind.

[Campbell Ritchie]

We all do things like that