byte... x

[Ramm Kummar]

class AddVarargs {
static void go(int x, int y) { System.out.println("int,int");}
static void go(byte... x)  // What does the code byte... x symbolises. Is it go(byte x, byte y)
{ System.out.println("byte... "); }
public static void main(String[] args) {
byte b = 5;
go(b,b); // 
}
}    

[Jesper de Jong]

The "..." notation is to specify that the method has a variable number of arguments. See Varargs.

static void go(byte... x)  // What does the code byte... x symbolises. Is it go(byte x, byte y) 

No, this does not mean the same as go(byte x, byte y). It is more or less the same as this:

static void go(byte[] x)

[Sagar Rohankar]

Its called varargs
You can pass an arbitrary number of arguments to the method.New feature added in Java 5
More information provided by varargs + Java Google

[Ankit Garg]

Hmm... Sachin your name is weirdly same as Sachin Ramesh Tendulkar. Is this your original name because according to the javaranch naming policy, you have to use your actual name as your display name...

[Sagar Rohankar]

Ankit Garg wrote:Hmm... Sachin your name is weirdly same as Sachin Ramesh Tendulkar

http://www.coderanch.com/t/437097/Java-General-beginner/java/Blocks