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What is the following XSLT program doing ?

Mustafa Garhi
Ranch Hand

Joined: Nov 05, 2008
Posts: 111
package xslt;

import java.io.File;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

import org.w3c.dom.Document;

public class DOMXslt
{
public static void main(String[] args) throws ParserConfigurationException
{
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.newDocument();

try
{
File datafile = new File(args[1]);
document = builder.parse(datafile);
DOMSource source = new DOMSource(document);

TransformerFactory tFactory = TransformerFactory.newInstance();
File stylesheet = new File(args[0]);
StreamSource stylesource = new StreamSource(stylesheet);
Transformer transformer = tFactory.newTransformer(stylesource);


StreamResult result = new StreamResult(System.out);
transformer.transform(source, result);
}
catch (Exception e) {
e.printStackTrace();
}
}
}
Ulf Dittmer
Marshal

Joined: Mar 22, 2005
Posts: 39578
    
  27
This question has nothing to do with the SCDJWS exam -which this forum is all about- so I'll move it to a more appropriate place.


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Paul Clapham
Bartender

Joined: Oct 14, 2005
Posts: 18160
    
    8

First it takes the (presumably XML) file which is named in the program's second command-line parameter and parses it into a DOM. Then it transforms that DOM, using the (presumably XSLT) file which is named in the program's first command-line parameter, and writes the result to the console.

Since you originally posted the question in a forum about exams, here's a question: some of this processing is unnecessary. What is it and why?
 
 
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