The following code is from Bates, Bert and Kathy Sierra. "SCJP Sun® Certified Programmer for JavaTM 6 Study Guide" (Master Exam):
Because there is no no-arg (default) constructor I would assume that the compiler would complain something like this:
Numbers.java:13: cannot find symbol
symbol : constructor Numbers()
location: class Numbers
Numbers negatives = new Numbers();
But the code compiles without errors and the output is -3 -1 5! Apparently the var-arg constructor matches the call with no args. The same with methods: a method go(int... x) will be executed when calling go() and there is no method go() without parameters.
Maybe this is obvious to others (to me it was not), but it might be a good idea to to include a hint on that behaviour in exam preparation books...
There are two ways that you can call a var-args method. One of them is by supplying a list of individual arguments (and this includes passing zero arguments.) The other is to pass an array reference of the same (or a compatible) type. When you use the first method and you pass no arguments, the var-args array in the method will contain 0 elements. Also, notice that you can't pass both individual elements and an array at the point of the call (only pass either individual elements, or an array, but not both.)
All code in my posts, unless a source is explicitly mentioned, is my own.