characters and numbers seperation in a string

[praveen oruganti]

I am having string like "65234Markets6713Investments".

I need to seperate this string as 65234,Markets,6713,Investments.


I have used the logic like :

   

public static void main(String[] args) {
		String s = "65234Markets6713Investments";
		StringBuffer sb = new StringBuffer();
		int pos = 1;
		char[] ch = s.toCharArray();
		for (int i = 0; i < ch.length; i++) {

			if (Character.isDigit(ch[i])) {
				pos = 1;
				sb.append(ch[i]);
			} else {
				if (pos == 1) {
					sb.append(',');
				}
				sb.append(ch[i]);
				pos++;
			}
		}
		System.out.println(sb.toString());
	}



 

But i am able to get the ouput like 65234,Markets6713,Investments.

can any one help me out in this.

[nek thomas]

Praveen, you might wanna try this....

public static void main(String[] args) {
String s = "65234Markets6713Investments";
StringBuffer sb = new StringBuffer();
int pos = 1;
char[] ch = s.toCharArray();
for (int i = 0; i < ch.length; i++) {

if (Character.isDigit(ch[i])) {
if(pos!=1)
{
pos=1;
sb.append(',');
}
sb.append(ch[i]);

} else {
if (pos == 1) {
sb.append(',');
}
sb.append(ch[i]);
pos++;
}
}
System.out.println(sb.toString());
}




This gives this result

65234,Markets,6713,Investments



Nek

[praveen oruganti]

Yes now it's working.

[Seetharaman Venkatasamy]

You can try this

    

String searchString = "(\\d+)";
			String str = "seethu23ashok475678fdertyu7fr";
			String[] st = str.split(searchString);
			int i = 0;
			for(String s : st){
				if( i == 0 ){
                                       if(!s.equals(""))
					str = str.replace(s,s+",");
				}else if(i == st.length-1){
					str = str.replace(s,","+s);
				}else{
					str = str.replace(s,","+s+",");
				}
				i++;
			}
			System.out.println(str);

[Rob Spoor]

If we're going to throw around solutions, here's mine:

String s = "65234Markets6713Investments";
StringBuilder sb = new StringBuilder();
int length = s.length();
if (length > 0)
{
    char last = s.charAt(0);
    sb.append(last);
    for (int i = 1; i < length; i++)
    {
        char c = s.charAt(i);
        if (Character.isDigit(c) != Character.isDigit(last)) // switched from digit to non-digit or vice versa
        {
            sb.append(',');
        }
        sb.append(c);
        last = c;
    }
}
System.out.println(sb.toString());  

[Seetharaman Venkatasamy]

its really beautiful Rob,

[Rob Spoor]

Of course it is
But thanks for the compliment.

[Garrett Rowe]

Since no one has posted the obligatory cryptic regex solution, I guess I'll provide one:

public class RegexSolution {

   public static void main(String[] args) {
     String s = "65234Markets6713Investments";
     String[] tokens = s.split("((?<=\\d+)(?=(\\p{Alpha})+))|((?<=(\\p{Alpha})+)(?=\\d+))");
     for (String tok : tokens) {
        System.out.println(tok);
     }
   }
}

[manepalli rajesh]

how to write the following condition can someone help me

1. the string should be like the following
You may use letters, numbers, underscores, and one dot (.) , i think with regular expressions we can do it.

2. one more string should be in the below format.
Use 6 to 32 characters, no spaces.

please somebody help me. this validation i am doing in serverside.

[Campbell Ritchie]

Please don't add a new question to somebody else's thread. That question probably merits a thread of its own, with a link to this thread if the patterns are similar.