Socket program for linux

[R Sugan]

Hi,

I tried to develop socket program for asterisk connection.I able to run successfully from remote host in windows.But i didn't able run that same socket program in Linux machine..


This is My Socket code

   
import java.io.BufferedReader;
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.net.*;
import java.sql.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import org.asteriskjava.manager.ManagerConnection;
import org.asteriskjava.manager.event.*;
public class Asteriskpd1 extends HttpServlet //implements  ManagerEventListener
{
	

 public void init(ServletConfig config) throws ServletException
 {
	 
	 
	 super.init(config);                  
	  searcher = new Thread();
	  searcher.start(); 
	  while (true) 
	  { 
	 try  
	 {  
	
	 Socket s=new Socket("xxx.xxx.x.xxx",5038);  
	 DataInputStream din=new DataInputStream(s.getInputStream());	
	 DataOutputStream dout=new DataOutputStream(s.getOutputStream());
	 PrintWriter wr=new PrintWriter(new  
	 OutputStreamWriter(s.getOutputStream()),true);  
	 wr.println("Hi Server...");  
	 wr.flush();  
	 BufferedReader br=new BufferedReader(new  InputStreamReader(s.getInputStream()));  

	 System.out.print("modified");
	    	
	    	 	System.out.print("nummmmmmmmm");
	     	 	wr.println("Action: login");
	    		 wr.println("Username: admin");
	    		 wr.println("Secret: amp111\r\n\r\n");
	    		 wr.println("Action: Originate");
	    		 wr.println("Channel: SIP/NBE/xxxxxxxxxx");
	    		
	    		 wr.println("Context: from-internal");
	    		 wr.println("Exten: 333");
	    		 wr.println("Priority: 1");
	    		 wr.println("Callerid: xxxxxxxxxx");
	    		 wr.println("Timeout: 30000\r\n\r\n");
	    
	    

		  int i=0;
		   while (i==0) 
			{
		        event=br.readLine();
		        System.out.println(event); 
			}

	 }
	 catch(Exception e)
	 	{
		 e.printStackTrace();
		 }  
try 
{
			
searcher.sleep(500);
} 
 catch (InterruptedException ignored) 
{ 
}
	 
 }
	 }
	 
	 }



 

]



Output:
i am getting this error

Response :Error
Message: Missing action in request

[Joe Ess]

It's a bad idea to classes like PrintWriter and BufferedReader when working with sockets as end-of-line characters are platform-dependent: don't println to a socket

[R Sugan]

Hi,

Thanks for your response.I changed my Socket program wr.print instead of wr.println.But am getting the same error message.Please give any solution to solve this problem.That is very helpful to do contious this process.


Regards,
Suganya.

[Ulf Dittmer]

Please post the code you're now using.

What's with the "searcher" Thread? Is that supposed to do something? Where is the variable defined?

[R Sugan]

Hi,

Just name for thread.I tried to develop socket program for asterisk connection.I able to run successfully from remote host in windows.But i didn't able run that same socket program in Linux machine..

This the my java code.

    
import java.io.BufferedReader;
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.net.*;
import java.sql.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import org.asteriskjava.manager.ManagerConnection;
import org.asteriskjava.manager.event.*;
public class Asteriskpd extends HttpServlet //implements  ManagerEventListener
{
static String campaign2;
static String campaign1; 
static String ratio;
String ratio1;
String freechannels;
String extnum;
String campaign4;
String agentcount;
String ratio2;
String phoneno_count;
String attempt;
String agentcount1;
String ratio3;
String extnum1;
String agent;
Thread searcher;
PrintWriter out = null;
BigInteger Lastnumber;
String event;
String num;
	 

 public void init(ServletConfig config) throws ServletException
 {
	 
	  Connection mysqlConn = null;
	  super.init(config);                  
	  searcher = new Thread();
	  searcher.start();  
	  while (true) 
	  { 
	 try  
	 {  
		
	 String Password;
	 Socket s=new Socket("xxx.xxx.x.xx",5038);  
	 DataInputStream din=new DataInputStream(s.getInputStream());	
	 DataOutputStream dout=new DataOutputStream(s.getOutputStream());
	 PrintWriter wr=new PrintWriter(new  
	 OutputStreamWriter(s.getOutputStream()),true);  
	 wr.println("Hi Server...");  
	 wr.flush();  
	 BufferedReader br=new BufferedReader(new  InputStreamReader(s.getInputStream()));  

	         System.out.print("modified");
	    	
	    	 System.out.print("nummmmmmmmm");
	     	 	 wr.println("Action: login");
	    		 wr.println("Username: admin");
	    		 wr.println("Secret: amp111\n\n");
	    		 wr.println("peopletech");
	    		 wr.println("Action: Originate");
	    		 wr.println("Channel: SIP/NBE/XXXXXXXXXXXX");
	    		
	    		 wr.println("Context: from-internal");
	    		 wr.println("Exten: 333");
	    		 wr.println("Priority: 1");
	    		 wr.println("Callerid: XXXXXXXXXXXXX");
	    		 wr.println("Timeout: 30000\n\n");
	    

		  int i=0;
		   while (i==0) 
			{
		        event=br.readLine();
		        System.out.println(event); 
			}

	 }
	 catch(Exception e)
	 	{
		 e.printStackTrace();
		 
		 }  
	 try {
			
		   searcher.sleep(500);
		  	} 
		  catch (InterruptedException ignored) { }
	 
 }
	 }
	 
	 }

Output:
i am getting this error

Response :Error
Message: Missing action in request

[Ulf Dittmer]

Just name for thread.

Well, it doesn't do anything, so you might as well delete it, lest someone looks at the code and assumes that it's doing something.

You're still using println with a Socket.

What's with the two newline characters after Timeout and Secret - are you sure that those do the right thing?

It's also a bit weird to do anything this involved in a servlet's init method; is this a load-on-startup servlet? If so, you should use a servlet context listener instead, and start whatever it's supposed to be doing in a separate thread (assuming that it's a long-running operation).

[R Sugan]

Hi,

Thanks for your response.I changed my code print instead of println.The two newline characters after Timeout and Secret this is correct way for sterisk api command.Am getting the same error....


Regards,
Suganya.

[Ulf Dittmer]

If you're now using print instead of println, then you're in all likelihood missing some newline characters. That's why I asked you to post your current code.

Are you certain that it's OK to send two "Action" commands in a row?

From http://www.voip-info.org/wiki/view/Asterisk+manager+Example%3A+Login:

Don't forget that you have to end your request with \r\n\r\n (two CrLfs), that's ascii characters 13, 10, 13 and 10 successively.

[R Sugan]

Hi,
This is My changed code.But am also getting the same error....

  
import java.io.*;
import java.net.*;
public class Asteriskpd1 
{

static String event;

public static void main(String[] args) throws IOException
 {	 

 
	 try  
	 {  
		
	 
	 Socket s=new Socket("xxx.xxx.x.xx",5038);  
	 DataInputStream din=new DataInputStream(s.getInputStream());	
	 DataOutputStream dout=new DataOutputStream(s.getOutputStream());
	 PrintWriter wr=new PrintWriter(new  
	 OutputStreamWriter(s.getOutputStream()),true);  
	  
	 wr.flush();  
	 BufferedReader br=new BufferedReader(new  InputStreamReader(s.getInputStream()));  

	        
	     	 	 wr.print("Action: login");
	    		 wr.print("Username: admin");
	    		 wr.print("Secret: amp111 \r\n\r\n");
	    		
	    		 wr.print("Action: Originate");
	    		 wr.print("Channel: SIP/NBE/XXXXXXXXXXXX");
	    		
	    		 wr.print("Context: from-internal");
	    		 wr.print("Exten: 333");
	    		 wr.print("Priority: 1");
	    		 wr.print("Callerid: XXXXXXXXXXXXX");
	    		 wr.print("Timeout: 30000 \r\n\r\n");
	    

		  int i=0;
		   while (i==0) 
			{
		        event=br.readLine();
		        System.out.println(event); 
			}

	 }
	 catch(Exception e)
	 	{
		 e.printStackTrace();
		 
		 }  
	 
	 
 
	 }
	 
	 }


Regards,
Suganya.



  

[Ulf Dittmer]

I'd be surprised if it was possible to send command without separating them by a newline character, or some such delimiter.