# How to avoid rounding while BigDecimal division

Anand Kapadi

Greenhorn

Posts: 26

posted 7 years ago

Hi,

I am trying to divide two BigDecimal numbers like this

BigDecimal startDateIndexPointValue = new BigDecimal(startDateIndexedValue.toString());

BigDecimal endDateIndexPointValue = new BigDecimal(endDateIndexedValue.toString());

// where startDateIndexPointValue = 2028, endDateIndexPointValue = 2047

BigDecimal intermediateValue;

intermediateValue = endDateIndexPointValue.divide(startDateIndexPointValue, 5, RoundingMode.HALF_UP);

The problem is that this using this precision and using the rounding mode, I am not getting the exact intermediate value.

I need the intermediate value for further calculation.

for e.g.

if I use windows calculator on these values

startDateIndexPointValue = 2028

endDateIndexPointValue = 2047

2047/2028 = intermediate value = 1.0093688362919132149901380670611

However, If i use the same values in BigDecimal division using the above rounding method,

i get the value of intermediate value as 1.00937

I cannot use RoundingMode.UNNECCESSARY, since BigDecimal division using this RoundingMode would throw a Runtime Arithmetic Exception.

Is there any way to avoid BigDecimal RoundingMode while division?

i.e. I do not want to perform any rounding for the intermediate value during division.

Thanks,

Anand

I am trying to divide two BigDecimal numbers like this

BigDecimal startDateIndexPointValue = new BigDecimal(startDateIndexedValue.toString());

BigDecimal endDateIndexPointValue = new BigDecimal(endDateIndexedValue.toString());

// where startDateIndexPointValue = 2028, endDateIndexPointValue = 2047

BigDecimal intermediateValue;

intermediateValue = endDateIndexPointValue.divide(startDateIndexPointValue, 5, RoundingMode.HALF_UP);

The problem is that this using this precision and using the rounding mode, I am not getting the exact intermediate value.

I need the intermediate value for further calculation.

for e.g.

if I use windows calculator on these values

startDateIndexPointValue = 2028

endDateIndexPointValue = 2047

2047/2028 = intermediate value = 1.0093688362919132149901380670611

However, If i use the same values in BigDecimal division using the above rounding method,

i get the value of intermediate value as 1.00937

I cannot use RoundingMode.UNNECCESSARY, since BigDecimal division using this RoundingMode would throw a Runtime Arithmetic Exception.

Is there any way to avoid BigDecimal RoundingMode while division?

i.e. I do not want to perform any rounding for the intermediate value during division.

Thanks,

Anand

Campbell Ritchie

Sheriff

Posts: 48972

60

posted 7 years ago

Unless you divide by a number whose prime factors only include 2 and 5, every division will recur, and go on to infinity. So you must round somewhere for BigDecimal for any number not a multiple of 2 and 5 only. 2048 is a multiple of 2 only, but 2047 isn't. so you must round. Choose a larger precision for your rounding.

Rama Krishna

Ranch Hand

Posts: 110

posted 6 years ago

I guess, if you wanted the calculator's precision and scale, in BigDecimal you ask or specify, isn't it rather than setting the scale to a small value as 5.

Or did you find an alternative?

Regards

Krishna

Campbell Ritchie wrote:Unless you divide by a number whose prime factors only include 2 and 5, every division will recur, and go on to infinity. So you must round somewhere for BigDecimal for any number not a multiple of 2 and 5 only. 2048 is a multiple of 2 only, but 2047 isn't. so you must round. Choose a larger precision for your rounding.

I guess, if you wanted the calculator's precision and scale, in BigDecimal you ask or specify, isn't it rather than setting the scale to a small value as 5.

Or did you find an alternative?

Regards

Krishna