Question about scanner.hasNext(".")

[Barry Burd]

The way I figure it, the following code should output

true
B

because the "data" file contains five characters, none of which have yet been read. Instead, the code outputs

false
B

Why?

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class UseNextChar {

	public static void main(String[] args) throws FileNotFoundException {
		Scanner scanner = new Scanner(new File("data"));

		System.out.println(scanner.hasNext("."));
		System.out.print(scanner.findWithinHorizon(".",0).charAt(0));

	}
}

[David Newton]

What does the input file look like? IIRC Scanner breaks up the input based on whitespace by default, so a "." would match only a single character.

(This is from memory--don't trust me.)

[Rob Spoor]

You're right David:

Returns true if the next token matches the pattern constructed from the specified string.

Since a token is constructed using whitespace as delimiter hasNext(".") would indeed return true only if the token was a single character.