Ajax: ResponseXML is null

[Deepika Singh]

hi all,

I have started doing an application using ajax but I am getting the responseXML is null.

the respective code for the ajax :-

function AjaxSubmit(firstRec, init)
{
	
	alert("HEllo................ start of ajax function................");
	var tabObj = document.getElementById('dataTable');
	var indObj = document.getElementById('indicatorRegion2');

	
	urlArr = new Array();
	tabObj.style.display = '';
	indObj.style.display = '';
	
		resetTable(tabObj, 1);
		alert(".... inside of ajax function................");
	
	try
   	{   
   	// Firefox, Opera 8.0+, Safari    
   		xmlHttp=new XMLHttpRequest();    
   	}
	catch (e)
	{    // Internet Explorer    
		try
     		{
     		    xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");   
     		}
	    catch (e)
	    {
	          try
       		  {
       		          xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");        
       		  }
		      catch (e)
		      {
		              alert("Your browser does not support AJAX!");        
		              return false;        
		      }
		 }
   	}	
	alert("....first record>>>."+firstRec);
	var url = "hdiits.htm?actionFlag=get;
		xmlHttp.onreadystatechange = function()
	{
		if(xmlHttp.readyState == 4) 
		{     
			if(xmlHttp.status == 200) 
			{
			alert(xmlHttp.responseText);
			var XMLtext=xmlHttp.responseXML;
			alert(".... inside of ajax function......value of XMLtext.........."+XMLtext);
				var XMLDoc = xmlHttp.responseXML.documentElement;
				
				alert(".... inside of ajax function......value of xmlDoc.........."+XMLDoc);
				
				indObj.style.display = 'none';
				if(XMLDoc!=null)
				{

var abc = XMLDoc.getElementsByTagName('value');
('com.tcs.sgv.fms.valueobject.PaginationCustomVO');
var displayData = XMLDoc.getElementsByTagName('com.tcs.sgv.wf.valueobject.WfDocNotificationListVo');
					
									
					var bColor = "";
					if((rSize==0)||(displayData.length==0))
					{
						alert("No Records found to display...");
						return;
					}	
					for (var i=0 ; i < displayData.length ; i++ )
					{
						

						if((i%2)==0)
							bColor = "rgb(255,255,255)";
						else
							bColor = "rgb(233,233,233)";
							
						RSubject = displayData[i].childNodes[1].text;
						RNum = displayData[i].childNodes[2].text;						
	  					RReferenceNumber = displayData[i].childNodes[3].text;	
	  					RDescription = displayData[i].childNodes[4].text;		
	  					RFromUser = displayData[i].childNodes[5].text;	
	  					RRecvDate = displayData[i].childNodes[6].text;	
	  					RLocation = displayData[i].childNodes[7].text;	
	  					RPriority = displayData[i].childNodes[8].text;	
	  					urlArr[url] = RReferenceNumber;
	  					
	  					var row = tabObj.insertRow();	
	  					row.style.backgroundColor = bColor;
	  					var cell1=row.insertCell(0);
						var cell2=row.insertCell(1);
						var cell3=row.insertCell(2);
						var cell4=row.insertCell(3);
						var cell5=row.insertCell(4);
						var cell6=row.insertCell(5);
						var cell7=row.insertCell(6);
						var cell8=row.insertCell(7);
				
						
						
												                                                                                  cell2.innerHTML=RSubject;
						
						if(RReferenceNumber=='#')	
							cell3.innerHTML=RNum;
						else
							cell3.innerHTML='<a >'+RNum+'</a>';
						cell4.innerHTML=RDescription;
						cell5.innerHTML=RFromUser;
						cell6.innerHTML=RRecvDate;
						cell7.innerHTML=RLocation;
						cell8.innerHTML=RPriority;
						
					}
						
  														else
				{
					alert("Error Encountered");
				}  
			}
			
		}
    }
	xmlHttp.open("POST", encodeURI(url) , true);    
	xmlHttp.setRequestHeader("Content-Type", "text/xml; charset=iso-8859-1");
	xmlHttp.send(encodeURIComponent(null));
	
}

[Sagar Rohankar]

Please UseCodeTags
Also post the server side code, where you're constructing the XML response.

[Eric Pascarello]

Read and follow this: http://radio.javaranch.com/pascarello/2006/09/12/1158096122600.html

Eric