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Beizer curve with three points?

Bobby Sharma
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Joined: Mar 18, 2008
Posts: 574
    
    1

According to API documentation of the GeneralPath.curveTo :


public void curveTo(float x1,
float y1,
float x2,
float y2,
float x3,
float y3)

Adds a curved segment, defined by three new points, to the path by drawing a Bézier curve that intersects both the current coordinates and the coordinates (x3, y3), using the specified points (x1, y1) and (x2, y2) as Bézier control points.

Parameters:
x1, y1 - the coordinates of the first Béezier control point
x2, y2 - the coordinates of the second Bézier control point
x3, y3 - the coordinates of the final endpoint


what's this final endpoint ? I am completely unable to draw meaningful from this function.

I googled and found that Cubic curve usually has four points but here we see only three points.Please provide me with
helpful information and explain how this function works?

best regards,
Omi


Back to Java , again.
Mike Simmons
Ranch Hand

Joined: Mar 05, 2008
Posts: 3013
    
  10
A GeneralPath has a "current point" which is basically the last point that was added to the path. That is used as the first point in the Bezier curve. The next three points are the ones that you supply in the arguments, for a total of four points.
Bobby Sharma
Ranch Hand

Joined: Mar 18, 2008
Posts: 574
    
    1

Oh! I see , that's new to me.

thanks big fella
 
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